9x^2+6x+4=27

Solution for 9x^2+6x+4=27 equation:

9x^2+6x+4=27

We move all terms to the left:

9x^2+6x+4-(27)=0

We add all the numbers together, and all the variables

9x^2+6x-23=0

a = 9; b = 6; c = -23;
Δ = b2-4ac
Δ = 62-4·9·(-23)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12\sqrt{6}}{2*9}=\frac{-6-12\sqrt{6}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12\sqrt{6}}{2*9}=\frac{-6+12\sqrt{6}}{18}
$